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ARTICLETechnical article

Fouling Allowance in Oil-Water Cooler Performance

  • Chenfan Power
Fouling Allowance in Oil-Water Cooler Performance: technical review table
First article table, reproduced without adding or changing values. See the article for assumptions and application boundaries.

A cooler guarantee can specify a clean bundle or an added fouling resistance. Put these on the same area basis before comparing thermal duty. DOE’s heat-transfer treatment relates total resistance, overall coefficient and the mean temperature difference [1]; the clean factory result does not measure future deposits.

Express all resistances on a common area basis before adding them. In a simplified overall coefficient, 1/U = 1/hoil + Rf,oil + Rwall + Rf,water + 1/hwater. U and h are W/(m²K); resistance terms are m²K/W. Rwall represents the complete separating-wall assembly; a double-wall construction also needs its inter-wall contact or gap resistance included. Cylindrical tubes require area conversion between their inner and outer surfaces.

Define what the allowance covers

Performance statementRequired basisEvidence
Clean factory capacitySpecified fluids, flows and temperaturesMeasured duty and uncertainty
Design fouled capacitySpecified side-by-side fouling resistancesCalculation using the agreed design assumptions
Installed service performanceActual water quality, deposit state and hydraulicsFour temperatures, flows and inspection evidence

A smaller U can have several causes

Record the water chemistry and expected maintenance conditions attached to the rating. Hardness, solids or biological growth can create different deposits and cleaning needs. “Suitable for cooling water” is not a sufficient water specification.

Maintenance evidence can distinguish a blocked flow path from loss of thermal performance: transformer guidance identifies debris and sludge in oil-water cooler tubes [2]. Check flow and obstruction before assigning the entire drop in apparent U to deposit resistance.

Carry fouling resistance into duty

Assume clean overall coefficient 500 W/(m²·K) on one consistent area basis and added fouling resistance 0.001 m²·K/W. Fouled U is 1/(1/500+0.001) = 333.3 W/(m²·K). For 10 m² and 20 K LMTD, duty falls from 100 to 66.67 kW if boundary temperatures remain fixed. Separate that prediction from a clean factory test.

References

  1. U.S. Department of Energy, DOE-HDBK-1012/2-92, Thermodynamics, Heat Transfer, and Fluid Flow, Volume 2, 1992.
  2. U.S. Bureau of Reclamation, FIST Volume 3-30, Transformer Maintenance, 2000.
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