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GSU Loading on the Generator Capability Curve

  • Chenfan Power

A generator can remain inside its capability curve while its generator step-up transformer exceeds a winding-current limit. The mismatch usually appears when a dispatch discussion uses megawatts and treats reactive power as a separate matter. Both travel through the transformer. Set the general power-transformer specification under IEC 60076-1 [1].

For a balanced three-phase operating point, apparent power is S = √(P² + Q²), and terminal current is I = S/(√3 V). Use P in watts, Q in vars, V as line-to-line RMS volts and I in amperes. These relations assume sinusoidal steady operation; they do not describe an unbalanced fault or harmonic heating.

GSU Loading on the Generator Capability Curve: technical review table
First article table, reproduced without adding or changing values. See the article for assumptions and application boundaries.

Draw the transformer boundary at the actual voltage

If the low-voltage winding permits current ILV, its current boundary on the P–Q plane is P² + Q² ≤ 3VLV²ILV². Lower terminal voltage shrinks this circle. A constant MVA circle drawn at nameplate voltage can therefore hide a low-voltage current problem.

The high-voltage winding needs its own check. Use the grid-side voltage and include losses and the actual tap ratio when translating the operating point. The generator capability curve may depend on terminal voltage, cooling conditions and excitation limits. Overlaying a single curve without those conditions gives a false intersection.

A plotting record that exposes the mismatch

Plot layerInput retainedQuestion answered
Generator envelopeTerminal voltage, cooling state, curve revisionCan the machine sustain this P–Q point?
LV current circleActual LV voltage and permissible currentDoes the generator-side winding overload?
HV current boundaryGrid voltage, tap and lossesDoes the grid-side winding restrict the point?
Thermal qualificationDuration, ambient and cooling availabilityIs the point continuous or temporary?

Assume balanced 50 Hz service at P = 90 MW, Q = 40 Mvar and LV voltage 19.0 kV. Apparent power is √(90² + 40²) = 98.49 MVA and current is 2993 A. An assumed 2900 A continuous LV limit allows only √3 × 19 × 2.9 = 95.44 MVA at that voltage. The requested point exceeds the current boundary by about 93 A even though its apparent power is below 100 MVA. Exclude that point or establish an approved revised envelope.

Read the intersection before selecting a rating

Evaluate maximum export, maximum reactive supply, maximum reactive absorption and the lowest permitted terminal voltage. Identify which device defines each edge of the feasible region. A generator rotor limit and a transformer winding limit can meet at the same point for different reasons.

At an excluded dispatch point, identify the binding current, voltage or thermal constraint on the plot. A larger headline MVA rating may leave the voltage envelope, connections or cooling duty unresolved; revise the constraint that actually excludes the point.

For mineral-oil equipment, relate the loading assessment to operating temperature and thermal ageing [2].

References

  1. IEC, IEC 60076-1:2011, Power transformers – Part 1: General.
  2. IEC, IEC 60076-7:2018, Power transformers – Part 7: Loading guide for mineral-oil-immersed power transformers.
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