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ARTICLETechnical article

Unbalanced Three-Phase Load Flow with an Explicit Neutral

  • Chenfan Power

Short answer

Unbalanced load flow explicit neutral modelling matters on low-voltage networks with significant unbalance. A common three-wire reduction eliminates the neutral using an effectively grounded-neutral assumption. Kron reduction is a general elimination method: its accuracy depends on the retained variables and boundary conditions, and it does not inherently require every neutral node to be perfectly grounded. A four-wire model keeps the neutral as its own conductor with its impedance and its real grounding points, so neutral voltage can rise along the feeder. In an illustrative LV feeder with phase currents of 100, 60 and 40 A at unity power factor, neutral current is about 53 A; with 0.1 Ω of neutral impedance to the end, neutral voltage rises about 5.3 V, shifting phase-to-neutral voltages at customers by several volts in different directions. This changes voltage compliance results and neutral conductor loading. Models should include neutral impedance and grounding explicitly where unbalance is significant.

Table comparing unbalanced load flow explicit neutral models
Grounded-neutral three-wire approximation and explicit four-wire model compared

Two modelling approaches

Grounded-neutral three-wire approximation and explicit four-wire model compared
AspectGrounded-neutral approximationFour-wire
Neutral voltageAssumed zeroCalculated
GroundingImplicit, perfectExplicit impedances
Customer voltagePhase-to-earthPhase-to-neutral
Example neutral shift0 V≈ 5.3 V
  • Grounded-neutral three-wire approximation: the neutral is eliminated with its voltage treated as effectively zero; assess whether the actual grounding makes that approximation adequate. A general reduction can use different boundary assumptions.
  • Four-wire: neutral kept as a conductor; grounding at transformer, services and electrodes modelled as impedances to earth.

Neutral current and voltage

Illustrative example. LV feeder end with phase currents 100 A, 60 A and 40 A at unity power factor, phases at 0°, −120°, +120°; neutral impedance from transformer to end 0.1 Ω. Values chosen for demonstration.

I_N = 100∠0° + 60∠−120° + 40∠120° ≈ 50 − j17.3 A, |I_N| ≈ 52.9 A

V_N ≈ 52.9 × 0.1 ≈ 5.3 V

Phase-to-neutral voltages at the customer are the phase voltages minus the neutral voltage, so the heavily loaded phase loses voltage while a lightly loaded one may gain. A reduced model that fixes V_N = 0 would miss these shifts.

Where it matters

SituationEffect of explicit neutral
High unbalance on LVNeutral shift of several volts
Few grounding pointsLarger neutral voltage
Triplen harmonicsMore neutral current; see neutral-to-earth voltage
PV on one phaseVoltage rise on that phase increased
Balanced MV feedersSmall effect

Inputs for four-wire models

  1. Neutral conductor size and length per segment.
  2. Grounding points and their resistance.
  3. Phase connection of each customer; see distribution transformer phase swapping.
  4. Transformer neutral grounding.
  5. Load models per phase; delta-connected loads need care; see delta-connected loads in transformer models.

Results to report

  • Neutral voltage at each node.
  • Phase-to-neutral voltages at customers, not only phase-to-earth.
  • Neutral current against conductor rating.
  • Comparison with the chosen three-wire approximation, recording its neutral and grounding assumptions.

What this article does not cover

Diagnosis of broken or high-resistance neutral faults is not covered here.

Where this reasoning stops. The example uses a single lumped neutral impedance; real networks need distributed models.

Practical takeaway

Use four-wire models with explicit neutral impedance and grounding where LV unbalance is significant, report phase-to-neutral voltages at customers, and check neutral current against ratings.

Reference framework

  1. W. H. Kersting, Distribution System Modeling and Analysis (four-wire line models).
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